A capacitor has a capacitance of 2.6 x 10 -6 F. Inthe charging process, electron

Question

A capacitor has a capacitance of 2.6 x 10-6 F. Inthe charging process, electrons are removed from one plate andplaced on the other plate. When the potential difference betweenthe plates is 380 V, how many electrons have beentransferred? all i need to know is how to set up the problem i can do thecalculations on my own thanx =) A capacitor has a capacitance of 2.6 x 10-6 F. Inthe charging process, electrons are removed from one plate andplaced on the other plate. When the potential difference betweenthe plates is 380 V, how many electrons have beentransferred? all i need to know is how to set up the problem i can do thecalculations on my own thanx =)

Explanation / Answer

All righty... there are two steps: . 1   Find the charge on the capacitor . 2. Convert the charge to a number of electrons. .    For step 1,    you knowthat       charge = CV        where C and V are thecapacitance and the voltage. .     You are given C and V, soget charge. Watch your units. The charge will be in coulombs. .    For step 2,   use theconversion:     1 electron = 1.60 x10-19 Coulomb    . .       Convert the amount of charge,in Coulombs, from step 1 into a number of electrons. . Done!   Send me a private message if you have anyquestions.

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