Two charges are located onthe x axis: q 1 = +3.0 µCat x 1 = +4.0 cm,and q 2 = +3

Question

Two charges are located onthe x axis: q1 = +3.0 µCat x1 = +4.0 cm,and q2 = +3.0 µCat x2 = -4.0 cm. Two other chargesare located onthe y axis: q3 =+4.0 µCat y3 = +5.0 cm,and q4 = -2.0 µCat y4 = +7.0 cm. Find the netelectric field (magnitude and direction) at the origin.
I'm not really sure where tostart. Any break down of how to solve this and the equationsinvolved would be appreciated.
I'm not really sure where tostart. Any break down of how to solve this and the equationsinvolved would be appreciated.

Explanation / Answer

o charges are located onthe x axis: q1 = +3.0 µCat x1 = +4.0 cm,and q2 = +3.0 µCat x2 = -4.0 cm. Two other chargesare located onthe y axis: q3 =+4.0 µCat y3 = +5.0 cm,and q4 = -2.0 µCat y4 = +7.0 cm. Find the netelectric field (magnitude and direction) at the origin. ELECTRIC FIELD DUE TO A -VE CHARGE IS TOWARDS IT AND THAT DUE TO A+VE CHARGE IS AWAY FROM IT . by symmetry electric field is o due toQ1and Q2 . E due to Q4 is upwards and that due to Q3 IS DOWNWARDS and theybehave as vectors E due to the two charges atorigin=9*109*10-6*104 [4/25-2/49]=1.072*107 N/C

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