When the dried-up seed pod of a scotch broom plantsbursts open, it shoots out a

Question

When the dried-up seed pod of a scotch broom plantsbursts open, it shoots out a seed with an intial velocity of 2.62m/s at an angle of 60.5degrees above the horizontal. (1)If the seed pod is 0.455m above the ground, how long doesit take for the seed to land? (2)What horizontal distance does it cover during itsflight? When the dried-up seed pod of a scotch broom plantsbursts open, it shoots out a seed with an intial velocity of 2.62m/s at an angle of 60.5degrees above the horizontal. (1)If the seed pod is 0.455m above the ground, how long doesit take for the seed to land? (2)What horizontal distance does it cover during itsflight?

Explanation / Answer

The initial speed of the seed is u = 2.62 m/s The seed is shoot out at an angle of = 60.5oabove the horizontal. (1)The height of the seed pod above the ground is H = 0.455m The time taken by the seed to land is t = (u * sin/g) --------------(1) Here,g = 9.8 m/s2 Substituting the values in equation (1),we get t = (2.62 * sin(60.5o)/(9.8)) or t = 0.23 s (2)The horizontal distance covered by the seed during itsflight is R = (u2 * sin2/g) or R = ((2.62)2 * sin(2 *60.5o)/(9.8)) or R = 0.6 m

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