An air filled parallel plate capacitor has plates of area.0406m 2 and separation

Question

An air filled parallel plate capacitor has plates of area.0406m2 and separation of 2.5 x 10 ^ -6 m. (a) What is the capacitance for this setup? (b) Our capacitor is connected to a 550V battery, howmuch energy is stored in the capacitor? (c) If -1 mJ of work is performed by the capacitor'splates but it is never disconnected from the 550V battery, what isthe new seperation of the plates? An air filled parallel plate capacitor has plates of area.0406m2 and separation of 2.5 x 10 ^ -6 m. (a) What is the capacitance for this setup? (b) Our capacitor is connected to a 550V battery, howmuch energy is stored in the capacitor? (c) If -1 mJ of work is performed by the capacitor'splates but it is never disconnected from the 550V battery, what isthe new seperation of the plates?

Explanation / Answer

(a). Capacitance C = A / d where = permitivity of free space = 8.85 * 10 ^-12 C ^ 2 / N m ^ 2           A =Area = 0.0406m2           d= separation of plates = 2.5 x 10 ^ -6 m substitue values we get C value (b). Voltage V = 550 V So, energy stored in the capacitor E = ( 1/ 2) C V2

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