A storm cloud has a V=1.00x10 8 V relative to a tree. During a lightning, Q=50.0

Question

A storm cloud has a V=1.00x108V relative to a tree. During a lightning, Q=50.0C is transferredthrough this V and 1.00% of the energy is absorbed by thetree. How much H2O in the tree initially at 30.0°Cis boiled away? Specific heat of H2O=4186J/°C,boiling point is100°C, and a heat of vaporization is2.26x106J/kg. A storm cloud has a V=1.00x108V relative to a tree. During a lightning, Q=50.0C is transferredthrough this V and 1.00% of the energy is absorbed by thetree. How much H2O in the tree initially at 30.0°Cis boiled away? Specific heat of H2O=4186J/°C,boiling point is100°C, and a heat of vaporization is2.26x106J/kg.

Explanation / Answer

We know energy E = ( 1/ 2) Q ( V )                                = ( 1/ 2) * 50 * 1.00x108   J                                = 25 * 10 8 J Energy absorbed by the tree E ' = 1 % of E                                                  = 0.01 E                                                  = 25 * 10 6 J Thsi is utilised to evoparate the water M C dt + M L = 25 * 10 6 J from this Mass M = ( 25 * 10 6 J ) / ( C dt +L ) where dt = 100 -30 = 70            C= Specific heat of H2O=4186J/°C           L= heat of vaporization is 2.26x106J/kg substitue values weget answer                                = ( 1/ 2) * 50 * 1.00x108   J                                = 25 * 10 8 J Energy absorbed by the tree E ' = 1 % of E                                                  = 0.01 E                                                  = 25 * 10 6 J Thsi is utilised to evoparate the water M C dt + M L = 25 * 10 6 J from this Mass M = ( 25 * 10 6 J ) / ( C dt +L ) where dt = 100 -30 = 70            C= Specific heat of H2O=4186J/°C           L= heat of vaporization is 2.26x106J/kg substitue values weget answer

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