Q1 = 6.0 nC is at (0.30m, 0); Q2 = -1.0 nC is at (0, 0.10m);Q3 = 5.0 nC is at (0

Question

Q1 = 6.0 nC is at (0.30m, 0); Q2 = -1.0 nC is at (0, 0.10m);Q3 = 5.0 nC is at (0,0). What is the magnitude of the net force onthe 5.0 nC charge? A) 4.5 x 10^-6 N B) 7.2 x 10^-6 N C) 3.0 x 10^-6 N D) 9.0 x 10^-6 N E) 5.4 x 10^-6 N How do you solve this? Q1 = 6.0 nC is at (0.30m, 0); Q2 = -1.0 nC is at (0, 0.10m);Q3 = 5.0 nC is at (0,0). What is the magnitude of the net force onthe 5.0 nC charge? A) 4.5 x 10^-6 N B) 7.2 x 10^-6 N C) 3.0 x 10^-6 N D) 9.0 x 10^-6 N E) 5.4 x 10^-6 N How do you solve this?

Explanation / Answer

All 3 charges lie in the y-z plane Fy = 9 * 10E9 * 6 * 10E-9 * 5 * 10E-9 /.32 = 3 * 10E-6 Fz =  9 * 10E9 * -1 * 10E-9 * 5 * 10E-9 /.12 = 5 * 10E-6 F = (Fy2 +Fz2) = 5.4 * 10E-6 N

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