I\'m going insane working on this problem. I\'ve triedeverything. Please help me

Question

I'm going insane working on this problem. I've triedeverything. Please help me! Thanks!
Problem A 0.17-kg ball on a string is whirled on avertical circle at a constant speed. When the ball is at the threeo'clock position, the tension is 12 N. (a) What is the magnitude T of thetension at the twelve o'clock position?
(b) What is the magnitude T of thetension at the six o'clock position? I'm going insane working on this problem. I've triedeverything. Please help me! Thanks!
Problem A 0.17-kg ball on a string is whirled on avertical circle at a constant speed. When the ball is at the threeo'clock position, the tension is 12 N. (a) What is the magnitude T of thetension at the twelve o'clock position?
(b) What is the magnitude T of thetension at the six o'clock position?

Explanation / Answer

          Given that the mass of the ball is m = 0.17 kg           The tention in the string is T = 12 N                    (at 3'O clock position )         ------------------------------------------------------------------------                              At 3'O clock  position A the velocity                              Tention in the string is T = mVb2 / r                                                            12N = mVb2/ r                 This is the velocity of the ball       Then the tention in the stringin twelve O'clock position is                                    mVc2 /r = T + mg        since the body is movingwith constant vleocity V then Vb =Vc = Va then                                                              T= mVb2/r - mg                                     = 12N - mg                                     =---------- N     The tention in the string in sixO'clock position is                                 T= mVa2 / r +mg                                         =12 N + mg                                    = ---------- N                                         At 3'O clock  position A the velocity                              Tention in the string is T = mVb2 / r                                                            12N = mVb2/ r                 This is the velocity of the ball       Then the tention in the stringin twelve O'clock position is                                    mVc2 /r = T + mg        since the body is movingwith constant vleocity V then Vb =Vc = Va then                                                              T= mVb2/r - mg                                     = 12N - mg                                     =---------- N     The tention in the string in sixO'clock position is                                 T= mVa2 / r +mg                                         =12 N + mg                                    = ---------- N                                                                                               12N = mVb2/ r                 This is the velocity of the ball       Then the tention in the stringin twelve O'clock position is                                    mVc2 /r = T + mg        since the body is movingwith constant vleocity V then Vb =Vc = Va then                                                              T= mVb2/r - mg                                     = 12N - mg                                     =---------- N     The tention in the string in sixO'clock position is                                 T= mVa2 / r +mg                                         =12 N + mg                                    = ---------- N                                   

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