As shown in Figure 5-22, a force of magnitude 7.50 N pushesthree boxes with mass
ID: 1738861 • Letter: A
Question
As shown in Figure 5-22, a force of magnitude 7.50 N pushesthree boxes with masses m1 = 1.30 kg,m2 = 3.40 kg, andm3 = 5.80 kg.(a)Find the magnitude of the contact force between boxes 1 and 2 (b) Find the magnitude of the contact force between boxes 2and 3.As shown in Figure 5-22, a force of magnitude 7.50 N pushesthree boxes with masses m1 = 1.30 kg,m2 = 3.40 kg, andm3 = 5.80 kg.(a)Find the magnitude of the contact force between boxes 1 and 2 (b) Find the magnitude of the contact force between boxes 2and 3.
Explanation / Answer
Total force of magnitude that pushes 3 boxes is 7.50 N As F=m a and here 7.5 =(1.30+3.40+5.80) a so a =0.72 m/s2 a) magnitude of force between boxes 1 and 2 is F1=(m1+m2) a =(1.30 +3.40)0.72 =3.4 N b)force between box 2 and 3 is F2=(m2+m3) a =(3.40+5.80)0.72 =6.6 N I think it will help you. a) magnitude of force between boxes 1 and 2 is F1=(m1+m2) a =(1.30 +3.40)0.72 =3.4 N b)force between box 2 and 3 is F2=(m2+m3) a =(3.40+5.80)0.72 =6.6 N I think it will help you.Related Questions
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