In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg objectthrough a distance o

Question

In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg objectthrough a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object?
I know that the answer to part a is 471.73J
I can't get the answer to part b though.
(b) What magnitude force did he exert on the object during thelift, assuming the force is constant. (a) How much work did Arfeuille do on the object?
I know that the answer to part a is 471.73J
I can't get the answer to part b though.
(b) What magnitude force did he exert on the object during thelift, assuming the force is constant.

Explanation / Answer

Magnitude of force F = work / displacement                                  = work / height                                  = 471.73 J / 17.1 cm                                  = 471.73 J / 0.171 m                                  =2758.7 N

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