Two forces are applied to a 6.9 kg object: F 1 =7.3Nj and F 2 =1.2 Nk. What is t

Question

Two forces are applied to a 6.9 kg object: F1=7.3Nj and F2=1.2 Nk. What is the magnitude of theresulting acceleration of this object? I determined the resultant vector in Newtons usingPythagorean thorem. substituted N in F=ma and determined the acceleration to be1.07 m/s2. When I submitted this answer, it was marked wrong. Two forces are applied to a 6.9 kg object: F1=7.3Nj and F2=1.2 Nk. What is the magnitude of theresulting acceleration of this object? I determined the resultant vector in Newtons usingPythagorean thorem. substituted N in F=ma and determined the acceleration to be1.07 m/s2. When I submitted this answer, it was marked wrong.

Explanation / Answer

Net force acting on the object is F = F1 +F2                                                     = (7.3N)j + (1.2N)k Now the magnitude of the net force acting on the mass is                       F = [(7.3N)2 + (1.2N)2]                          = 7.398 N Now magnitude of the acceleration (a) of the object is                          a= F / m                            = (7.398N) / (6.9kg)                            = 1.072 m/s2 Now the magnitude of the net force acting on the mass is                       F = [(7.3N)2 + (1.2N)2]                          = 7.398 N Now magnitude of the acceleration (a) of the object is                          a= F / m                            = (7.398N) / (6.9kg)                            = 1.072 m/s2

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