Can someone help me out with the following question and showme the the steps! Th

Question

Can someone help me out with the following question and showme the the steps! Thank You! A rifle bullet is fired at an angle of 30 degrees to thehorizontal with an initial velocity of 2800m/s from the top of thecliff 180 m high. How far from the base of the cliff does it strikethe level ground below? Can someone help me out with the following question and showme the the steps! Thank You! A rifle bullet is fired at an angle of 30 degrees to thehorizontal with an initial velocity of 2800m/s from the top of thecliff 180 m high. How far from the base of the cliff does it strikethe level ground below?

Explanation / Answer

Vertical component of velocity = vsin=2800sin30 =1400m/s Horizontal component of velocity = vcos = 2800cos30 =2424.87 Total distance travelled in the y from max height toground. vf2=vi2+2ad vf=0 d1=vi2/-2a =(1400)2/-2(-9.8m/s2) = 100,000 m total distance from apex to ground = 100,000m + 180m =100180m Final velocity vf2=vi2+2ad vi2 =0 vf=2ad=2(-9.8m/s2)(-100180m) = 1401.26m/s. You could alternately combine these two steps into one and getthe same answer. vf2=vi2+2ad vf=vi2 +2ad =(14002 +2(-9.8m/s2)(d1-d1-180m))= 1401.26m/s 1) Find the total time the bullet is in the air. vf=vi + at -1401.26 = 1400m/s + (-9.8m/s2)t t = 285.84 2) Find how far it travels in the horizontal. x = vot + 1/2at2 a = 0 x = vot = (2424.87m/s)(285.84s) x = 693125 m a = 0 x = vot = (2424.87m/s)(285.84s) x = 693125 m

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