Question: A person standing in a truck moving at aspeed of 72km/h on a horizonta

Question

Question: A person standing in a truck moving at aspeed of 72km/h on a horizontal road releases a heavy box from hishand stretched to the outside of the truck. The box fell through aheight of 3m before hitting the ground. Neglect airresistance a) Determine the horizontal displacements of the truckand the box during the time the box is in the air. b) Determine the velocity with which the box hitsthe ground. a) Determine the horizontal displacements of the truckand the box during the time the box is in the air. b) Determine the velocity with which the box hitsthe ground.

Explanation / Answer

a) the time to hit the ground be t, we have: H = 3.0m = (1/2)gt2 =>t = (2*3.0m/9.8m/s2) = 0.78 s v=72km/h = 72*1000m/3600s = 20 m/s the horizontal distance D = vt = 20m/s* 0.78s = 15.6 m b) vx = 20m/s vy = gt = 9.8m/s2 * (0.78s) = 7.64m/s the speed hit the ground v = [(20m/s)2 + (7.64m/s)2] =21.41 m/s =>t = (2*3.0m/9.8m/s2) = 0.78 s v=72km/h = 72*1000m/3600s = 20 m/s the horizontal distance D = vt = 20m/s* 0.78s = 15.6 m b) vx = 20m/s vy = gt = 9.8m/s2 * (0.78s) = 7.64m/s the speed hit the ground v = [(20m/s)2 + (7.64m/s)2] =21.41 m/s

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