A ranger in a national park is driving at 35 mi/h when a dearjumps onto the road

Question

A ranger in a national park is driving at 35 mi/h when a dearjumps onto the road 200ft ahead of the vehicle. After a reactiontime t, the ranger applies the brakes to produce anacceleration a = -9.00 ft/s2. What is the maximum reaction time allowed if she is to avoidhitting the deer? A ranger in a national park is driving at 35 mi/h when a dearjumps onto the road 200ft ahead of the vehicle. After a reactiontime t, the ranger applies the brakes to produce anacceleration a = -9.00 ft/s2. What is the maximum reaction time allowed if she is to avoidhitting the deer?

Explanation / Answer

Then Vf = 0 at the dear. And Vi = 35mi/h = 51.333ft/s Deceleration = 9ft/s2 Using the kinematics equation of acceleration weget Distance travelled = (Vi2)/2a = 146.3949ft Therefore the distance the ranger has before he canapply brake is 200-146.3949 = 53.605ft Therefore maximum reaction time allowed = 53.605/51.333 = 1.044s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.