An electron is accelerated from rest through a potentialdifference of 3750 V. It

Question

An electron is accelerated from rest through a potentialdifference of 3750 V. It enters a region where the magneticfield is 4.0 mT perpendicular to the velocity of theelectron. Calculate the radius of the path this electron willfollow. A) 1.2 cm B) 2.2 cm C) 5.2 cm D) 3.2 cm E) 4.2 cm How do you solve this? An electron is accelerated from rest through a potentialdifference of 3750 V. It enters a region where the magneticfield is 4.0 mT perpendicular to the velocity of theelectron. Calculate the radius of the path this electron willfollow. A) 1.2 cm B) 2.2 cm C) 5.2 cm D) 3.2 cm E) 4.2 cm How do you solve this?

Explanation / Answer

potential difference V = 3750 V Speed of the electron after passes through the potentialdifference V is v = [ 2 V q / m ] where q = charge = 1.6 * 10 ^ -19 C            m= mass = 9.1 * 10 ^ -31 kg from this we find v value magnetic field B = 4 m T = 4 * 10 ^ -3 T Required radius R = m v / B q substitue values we get answer

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