First Generation Allele Frequencies: 2Cc=0.42 CC=0.49 cc=0.09 In light of findin
ID: 174066 • Letter: F
Question
First Generation Allele Frequencies: 2Cc=0.42 CC=0.49 cc=0.09
In light of finding out more about this population, you return to the ISS in year 2110 and observe a second generation. You find out that there was now 141 individuals living there. After you look at the census, you notice there was 53 males on the ISS. However, you also realize that 14 of females cannot have children (causes were not determined). For this problem, let's assume polygynous mating system.
1) Calculate loss of heterozygosity in population.
2) Calculate the percentage heterozygosity left after 4 generations. Assume we start with 100 percent heterozygosity.
Explanation / Answer
Answer:
In the first generation
allele frequencies 2Cc =0.42, CC=0.49, cc=0.09
The HW law is aplicable as here p+2pq+q = 1 i.e 2Cc+CC+cc = 0.42+0.49+0.09=1
Polygamous mating system is applied here means, one male has an exclusive relationship with two or more females.
Loss of heterozygosity (LOH) is a gross chromosomal event that results in loss of the entire gene and the surrounding chromosomal region.
The loss of H from one generation to the next genration = 1 / 2Ne
The proportion of heterozygotes in the fourth generation will be
Ne = Nf/(1+Nf)
The formula to calculate effective population size is: Ne = 4 * M * F / (M + F)
Where, the number of males and females (M and F) only includes breeding individuals.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.