A glass ball, ball A, of mass 5.0 g, movesat a velocity of 20.0 cm/s. It collide

Question

    A glass ball, ball A, of mass 5.0 g, movesat a velocity of 20.0 cm/s. It collides with a second glass ball,ball B, of mass 10.0 g, moving along the same line with a velocityof 10.0 cm/s. After the collision, ball A is still moving, but witha velocity of 8.0 cm/s.
What is ball B’s velocity after the collision? Please give step by step instruction A glass ball, ball A, of mass 5.0 g, movesat a velocity of 20.0 cm/s. It collides with a second glass ball,ball B, of mass 10.0 g, moving along the same line with a velocityof 10.0 cm/s. After the collision, ball A is still moving, but witha velocity of 8.0 cm/s.
What is ball B’s velocity after the collision? Please give step by step instruction

Explanation / Answer

            Giventhat the mass of the ball A is m1 = 5.0 g =5.0*10-3 kg            Initial velocity of A is U1 = 20.0 cm/s = 0.20 m/s            The second mass B is m2 = 10.0 g = 10.0*10-3kg            The velocity of second mass B is U2 = 0.1 m/s             Thefinal velocity of the ball A is V1 = 8.0 cm /s = 0.08 m/s ----------------------------------------------------------------------------------------------        From the conservation ofmomentum                                                m1*U1 + m2*U2 = m1*V1 + m2*V2                                                    Then V2 = (  m1*U1 + m2*U2 - m1*V1 ) /m2                                     =------------- m/s            This is the final velocity of the mass B

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