The window on the ground floor of a building stretches fromthe ground to the cei
ID: 1741196 • Letter: T
Question
The window on the ground floor of a building stretches fromthe ground to the ceiling and is 2.0 m high. When a ball is droppedfrom a window on one of the upper floors, it is observed that ittakes 0.10 seconds to hit the ground from the time that it reachesthe top of the ground-floor window. From what height above theground was the ball dropped? (Hint: First calculate the time taken for the ball to the fallfrom its release position to the top of the ground-floorwindow.) Thanks. The window on the ground floor of a building stretches fromthe ground to the ceiling and is 2.0 m high. When a ball is droppedfrom a window on one of the upper floors, it is observed that ittakes 0.10 seconds to hit the ground from the time that it reachesthe top of the ground-floor window. From what height above theground was the ball dropped? (Hint: First calculate the time taken for the ball to the fallfrom its release position to the top of the ground-floorwindow.) Thanks.Explanation / Answer
let ' t ' be the time taken by the ball to dropfrom the top of the window to the ground distace travelled in last 0.1 sec = 2 m accleration due to gravity = g velocity of the ball by the time it reached top of thewindow = v S = v t + gt^2 / 2 S = 2m g = 9.8 m/s^2 v = ? t = 0.1 sec plugging in the given values in the above relation wecan sovle for the velocity of the ball by teh time it reaches thetop of the window , ' v ' . if h be the height from the top of thewindwo to the upper floor where the ball is left to free fall h = v^2 / 2g . making use of above relation (h + 2m) gives the totalheight from the ground . making use of above relation (h + 2m) gives the totalheight from the ground .Related Questions
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