Hello, Can somebody please show me how to do thefollowing problem? Thanks. A par

Question

Hello,    Can somebody please show me how to do thefollowing problem? Thanks. A parallel-plate capacitor has 4.00cm2 plates that are separated by 8.00 mm with air between them. If a 12.0 V battery isconnected to this capacitor, how much energy does it store?
1 J
Hello,    Can somebody please show me how to do thefollowing problem? Thanks. A parallel-plate capacitor has 4.00cm2 plates that are separated by 8.00 mm with air between them. If a 12.0 V battery isconnected to this capacitor, how much energy does it store?
1 J

Explanation / Answer

. 1.   This is a two-step probelm: Firstyou must calculate the value of the capacitor based upon itsphysical parameters. After that, you can calculate engeryusing E = (1/2)*C*V2. 2.   C = capacitance =[(0)*(r)*(Area)]/[distancebetween plates] =[(r)*(Area)]/[(9.0E+9)*(4)*(d)] ; r = 1.0 3.   Convert cm to meters:   (4.00 cm2)*[meter/(100 cm)]2 = 400.0E-6meters2 4.   Convert mm to meters:   (8.00 mm)*[meter/(1000 mm)] = 8.0E-3 meters 5.   Calculate the capacitance using '2', '3',and '4'. 6.   C = [(1)*(400.0E-6meters2)]/[(9.0E+9)*(4)*(8.0E-3 meters) = 442.1E-15Farads 7.   E= Energy = (1/2)*(442.1E-15 Farads)*(12volts)2 = 31.8E-12 Joules .

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