Hi! I don\'t understand how equation I was derived fromm 1 u 1 + m 2 u 2 =m 1 v

Question

Hi! I don't understand how equation I was derived fromm1u1 + m2u2 =m1v1 + m2v2 How did they go from (10 x 10-3 v1) +(30 x 10-3 v2) = [10 x 10-3 x(-0.40)] + [30 x 10-3 x (0.20)] to v1 + 3v2 = 0.2 ? Hi! I don't understand how equation I was derived fromm1u1 + m2u2 =m1v1 + m2v2 How did they go from (10 x 10-3 v1) +(30 x 10-3 v2) = [10 x 10-3 x(-0.40)] + [30 x 10-3 x (0.20)] to v1 + 3v2 = 0.2 ? How did they go from (10 x 10-3 v1) +(30 x 10-3 v2) = [10 x 10-3 x(-0.40)] + [30 x 10-3 x (0.20)] to v1 + 3v2 = 0.2 ?

Explanation / Answer

(10 x 10-3 v1) + (30 x 10-3v2) = -4*10-3 +6*10-3 (10 x 10-3 v1) + (30 x 10-3v2) =2*10-3 Now taking 10-3 common on both sides weget             10v1 +30v2 =2 Now dividing with 10 on both sides we get                 v1 + 3v2 =0.2 (10 x 10-3 v1) + (30 x 10-3v2) =2*10-3 Now taking 10-3 common on both sides weget             10v1 +30v2 =2 Now dividing with 10 on both sides we get                 v1 + 3v2 =0.2 Now taking 10-3 common on both sides weget             10v1 +30v2 =2 Now dividing with 10 on both sides we get                 v1 + 3v2 =0.2

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