A power transmission line 50 km long has a total resistance of0.60. A generator

Question

A power transmission line 50 km long has a total resistance of0.60. A generator produces 100 V at 70 A. In order to reduceenergy loss due to heating of the transmission line, the voltage isstepped up with a transformer with a turn ratio of 100:1. a. What is the % of the orginal energy would be lost if thetransformer were not used? b. What % of the orginal energy is losted when thetransformer is used? A power transmission line 50 km long has a total resistance of0.60. A generator produces 100 V at 70 A. In order to reduceenergy loss due to heating of the transmission line, the voltage isstepped up with a transformer with a turn ratio of 100:1. a. What is the % of the orginal energy would be lost if thetransformer were not used? b. What % of the orginal energy is losted when thetransformer is used?

Explanation / Answer

   Powerproduced   P1   =   V* I   =   100 *70   =   7000   W    a.   Power lost intransmission lines withouttransformer   P2      =   i2* R   =   702 *0.6   =   2940   W       % powerwasted         =   (P2/ P1) * 100%   =   (2490 /7000) *100%   =   35.57   %    b.   Isecondary /Iprimary   =   Nprimary/ Nsecondary          Isecondary/ 70   =   1 /100   =>   current insecoondary   Isecondary   =   0.7   A        Powerlost   P3   =   0.72*0.6   =   0.249   W      % Power lost withtransformer         =   (P3/ P1) * 100%   =   (0.249/ 7000) *100%   =   0.0035   %          Isecondary/ 70   =   1 /100   =>   current insecoondary   Isecondary   =   0.7   A        Powerlost   P3   =   0.72*0.6   =   0.249   W      % Power lost withtransformer         =   (P3/ P1) * 100%   =   (0.249/ 7000) *100%   =   0.0035   %

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