I\'m having trouble with the following question. Wei Wei is pulling her 80.0 kg

Question

I'm having trouble with the following question.    Wei Wei is pulling her 80.0 kg sister up theside of a cliff with a rope. If Wei Wei does 999J of work in orderto accelerate her sister up the cliff at a rate of a=1.00 m/s^2. What is the height of the cliff?    When I looked through my notes, I found anequation that readys U=mgy . Is this the equation I would use?Thanks! I'm having trouble with the following question.    Wei Wei is pulling her 80.0 kg sister up theside of a cliff with a rope. If Wei Wei does 999J of work in orderto accelerate her sister up the cliff at a rate of a=1.00 m/s^2. What is the height of the cliff?    When I looked through my notes, I found anequation that readys U=mgy . Is this the equation I would use?Thanks!

Explanation / Answer

Force = Mass * Acceleration

999J = 80KG * 1.00m/s2 * distance

999/80 = 12.48 meters

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