Normal Force Frictional Force 10 N 2.3 N 15 N 3.8 N 20 N 5.1 N 25 N 6.6 N 30 N 7
ID: 1741796 • Letter: N
Question
Normal Force Frictional Force 10 N 2.3 N 15 N 3.8 N 20 N 5.1 N 25 N 6.6 N 30 N 7.4 N The table shows several values of measured frictional force forgiven normal forces in an experiment. Find the experimental valueof the coefficient of friction. (It is recommended that you fit thedata using Excel or other analysis software. Don't forget to setthe y-intercept as zero and round to the correct number ofsignificant figures.) Normal Force Frictional Force 10 N 2.3 N 15 N 3.8 N 20 N 5.1 N 25 N 6.6 N 30 N 7.4 N Normal Force Frictional Force 10 N 2.3 N 15 N 3.8 N 20 N 5.1 N 25 N 6.6 N 30 N 7.4 NExplanation / Answer
F = mu x F(normal) F normal force is given which is just mg (mass x gravity) mu is what you want 2.3 = mu x 10 = 2.3/10, so mu = 0.23 3.8 = mu x 15 = 3.8/15, so mu = 0.25 5.1 = mu x 20 = 5.1/20, so mu = 0.26 6.6 = mu x 25 = 6.6/25, so mu = 0.26 7.4 = mu x 30 = 7.4/30, so mu = 0.25
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