A crate of mass 9.10 kg is pulled up arough incline with an initial speed of 1.5

Question

A crate of mass 9.10 kg is pulled up arough incline with an initial speed of 1.55 m/s. The pulling force is 102 N parallel to the incline, which makes anangle of 19.4° with the horizontal. The coefficient ofkinetic friction is 0.400, and the crate is pulled 4.96 m. (a) How much work is done by the gravitationalforce on the crate?
1 J

(b) Determine the increase in internal energy of the crate-inclinesystem due friction.
2 J

(c) How much work is done by the 102 Nforce on the crate?
3 J

(d) What is the change in kinetic energy of the crate?
4 J

(e) What is the speed of the crate after being pulled 4.96 m?
5 m/s (a) How much work is done by the gravitationalforce on the crate?
1 J

(b) Determine the increase in internal energy of the crate-inclinesystem due friction.
2 J

(c) How much work is done by the 102 Nforce on the crate?
3 J

(d) What is the change in kinetic energy of the crate?
4 J

(e) What is the speed of the crate after being pulled 4.96 m?
5 m/s

Explanation / Answer

a. W=F*d W=mgsin*d W=9.1*9.8*sin19.4*4.96J b. W=fr*d W=kmgcos*d W=0.4*9.1*9.8*cos19.4*4.96J c. The resultant force is F-(F+fr)=F1 Then, W=F1*d W=F1*4.96J d. The change in KE KE=F1*4.96J e. F1=ma From this we get acceleration The velocity is given by, v2-u2=2as v2-0=2*a*4.96 v=9.92a m/s Hence we get by it.

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