Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

9. The Essex-6 artificial satellite, with its mass of 600 kg,is placed in a circ

ID: 1742218 • Letter: 9

Question

9. The Essex-6 artificial satellite, with its mass of 600 kg,is placed in a circular orbit and revolves around Earth with itsperiod T=6hr. Find (a) the satellite's altitude; (b) the satellite's orbital speed; (c) the gravitational force acting on the satellite. 9. The Essex-6 artificial satellite, with its mass of 600 kg,is placed in a circular orbit and revolves around Earth with itsperiod T=6hr. Find (a) the satellite's altitude; (b) the satellite's orbital speed; (c) the gravitational force acting on the satellite.

Explanation / Answer

PLEASE   RATE   MY  ANSWER . (a) using Keplers 3rd law, you get:    GMT2 = 42r3         whereT is the period and r is the radius of the orbit. . So...   6.67 x 10-11 * 5.98 x1024 * (6*3600)2 = 42 r3 . r = 1.6767 x 107 meters . to get the altitude, you have to subtract the radius of theEarth,   0.638 x 107 meters .     altitude = 1.6767 - 0.638 =    1.039 x107 meters =   10390km . (b) speed = distance / time = 2r / T = 2 * 1.6767 x 107 /6*3600 = .            =    4877 m/s . (c) Force = m v2 / r =   600* 48772 / 1.6767 x 107 = .               =    851.3 Newtons . r = 1.6767 x 107 meters . to get the altitude, you have to subtract the radius of theEarth,   0.638 x 107 meters .     altitude = 1.6767 - 0.638 =    1.039 x107 meters =   10390km . (b) speed = distance / time = 2r / T = 2 * 1.6767 x 107 /6*3600 = .            =    4877 m/s . (c) Force = m v2 / r =   600* 48772 / 1.6767 x 107 = .               =    851.3 Newtons