A 60 resistor and a 40 are connected in parallelto a 120V power supply. (a) What

Question

A 60 resistor and a 40 are connected in parallelto a 120V power supply. (a) What is the current though each resistor? (b) What is the total resistance of the combination? (c) If the resistance were connected in series, what would bethe current through each? What would be the voltage drop acrosseach? A 60 resistor and a 40 are connected in parallelto a 120V power supply. (a) What is the current though each resistor? (b) What is the total resistance of the combination? (c) If the resistance were connected in series, what would bethe current through each? What would be the voltage drop acrosseach?

Explanation / Answer

a) I60 = 120V/60 = 2A I40 = 120V/40 = 3A b) Req = 60||40 =60*40/(60+40) = 24 c) now R = 60 + 40 = 100 I = 120V/100 = 1.2 A I60 = I40 = I = 1.2A V60 = I60*60 = 1.2A*60 = 72V V40 = I40*40=1.2A*40 = 48V

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