Here is the answer i was given..can someone complete the mathso i may check my a

Question

Here is the answer i was given..can someone complete the mathso i may check my answer? ResponseDetails: Potential at point A is V = K{ [ ( 1 * 10 ^ - 6 )/ a ] + [ ( 3 * 10 ^ -6 ) / a ) + [ ( -4 * 10 ^ -6 ) / a ]} where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2            a = distance of point A from 1 C Or 3 C or -4C from triangle a ^ 2 + a ^ 2 = 1 ^ 2                               2 * a = 1                                        a= 0.707 m       substitue values we getanswer        
What does the final answer come out to? Here is the answer i was given..can someone complete the mathso i may check my answer? ResponseDetails: Potential at point A is V = K{ [ ( 1 * 10 ^ - 6 )/ a ] + [ ( 3 * 10 ^ -6 ) / a ) + [ ( -4 * 10 ^ -6 ) / a ]} where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2            a = distance of point A from 1 C Or 3 C or -4C from triangle a ^ 2 + a ^ 2 = 1 ^ 2                               2 * a = 1                                        a= 0.707 m       substitue values we getanswer         ResponseDetails: Potential at point A is V = K{ [ ( 1 * 10 ^ - 6 )/ a ] + [ ( 3 * 10 ^ -6 ) / a ) + [ ( -4 * 10 ^ -6 ) / a ]} where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2            a = distance of point A from 1 C Or 3 C or -4C from triangle a ^ 2 + a ^ 2 = 1 ^ 2                               2 * a = 1                                        a= 0.707 m       substitue values we getanswer         ResponseDetails: Potential at point A is V = K{ [ ( 1 * 10 ^ - 6 )/ a ] + [ ( 3 * 10 ^ -6 ) / a ) + [ ( -4 * 10 ^ -6 ) / a ]} where K = coulomb's constant = 8.99 * 10 ^ 9 N m ^ 2 / C^ 2            a = distance of point A from 1 C Or 3 C or -4C from triangle a ^ 2 + a ^ 2 = 1 ^ 2                               2 * a = 1                                        a= 0.707 m       substitue values we getanswer        

Explanation / Answer

Given Equation: V = K (q1/a + q2/a +q3/a)      Where K = 8.99X109 a = 0.707q1 = 1X10-6 q2 = 3X10-6q3 = -4X10-6 "Plug and Chug" V = (8.99X109)(1X10-6/.707 +3X10-6/.707 + -4X10-6/.707) =-9X10-10 = -900 V Hope that helps!

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.