A 0.300 kg pendulum bobpasses through the lowest part of its path at a speedof 3
ID: 1742657 • Letter: A
Question
A 0.300 kg pendulum bobpasses through the lowest part of its path at a speedof 3.30 m/s. (a) What is the tension in the pendulum cable at this point if thependulum is 80.0 cm long?N
(b) When the pendulum reaches its highest point, what angle doesthe cable make with the vertical?
°
(c) What is the tension in the pendulum cable when the pendulumreaches its highest point?
N (a) What is the tension in the pendulum cable at this point if thependulum is 80.0 cm long?
N
(b) When the pendulum reaches its highest point, what angle doesthe cable make with the vertical?
°
(c) What is the tension in the pendulum cable when the pendulumreaches its highest point?
N
Explanation / Answer
Given thatthe mass of the pendulum is m = 0.300 kg Speed at thebottom is U = 3.30 m/s Length ofthe pendulum is L = 80.0 cm = 0.80 m ---------------------------------------------------------------- (a) Thetention in the string at the bottom is T = mg + mU2 /L =------------ N (b) If the pendulum reaches theheighest point then mgh = (1/2)mU2 h= U2 / 2g = ---------- m This is the maximum height reached bythe mass from the bottom The angle = cos-1( 1 - h/L ) =-------- degrees The tention in thestring at the heighest point is T = mg cos =------------ N h= U2 / 2g = ---------- m This is the maximum height reached bythe mass from the bottom The angle = cos-1( 1 - h/L ) =-------- degrees The tention in thestring at the heighest point is T = mg cos =------------ N The angle = cos-1( 1 - h/L ) =-------- degrees The tention in thestring at the heighest point is T = mg cos =------------ N T = mg cos =------------ NRelated Questions
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