A light ray of wavelength 589 nm is incident at an angle? on the top surface of

Question

A light ray of wavelength 589 nm is incident at an angle? on the top surface of a block of sodium chloride surrounded by air, as shown in FigureP22.46. Figure P22.46 (a) Find the maximum value of ?for which the refracted ray will undergo total internal reflectionat the left vertical face of the block. 1wrong check mark Your answer differs from the correct answerby 10% to 100%. (b) Repeat the calculation for the case in which the sodium chloride block is immersed in ethyl alcohol. 2 degree (c) What happens if the block is immersed in carbon disulfide? 3

Explanation / Answer

   for the given problem consider the diagram asshown    to solve this we use snells law    from the diagram for the polysterenesurrounded byu air total internal reflection at the leftvertical    face requires that    3 > c        = sin-1(nair / np)        = sin-1(1.00 / 1.544)        =.........o    from the diagram    2 = 90.0o -3       = ..........o    sin1 = npsin2 / nair          <= (1.544)sin2 / 1.00             =..........    so from the above result we can see that anyangle of incidence <= 90o at the upper surfave will    yield total internalreflection         from the diagram    2 = 90.0o -3       = ..........o    sin1 = npsin2 / nair          <= (1.544)sin2 / 1.00             =..........    so from the above result we can see that anyangle of incidence <= 90o at the upper surfave will    yield total internalreflection         sin1 = npsin2 / nair          <= (1.544)sin2 / 1.00             =..........    so from the above result we can see that anyangle of incidence <= 90o at the upper surfave will    yield total internalreflection     

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