QuestionDetails: a.) Exactly four bright fringes are seen oneither side of the c

Question

QuestionDetails: a.) Exactly four bright fringes are seen oneither side of the central maximum when a difraction grating isilluminated with yellow-green light of wavelength =570nm.What is the maximum number of lines/m for the grating? b.) If violet light of frequency 7.9x10^14Hz is used with thissame grating, what is the highest order maximum that can beseen? QuestionDetails: a.) Exactly four bright fringes are seen oneither side of the central maximum when a difraction grating isilluminated with yellow-green light of wavelength =570nm.What is the maximum number of lines/m for the grating? b.) If violet light of frequency 7.9x10^14Hz is used with thissame grating, what is the highest order maximum that can beseen? QuestionDetails: a.) Exactly four bright fringes are seen oneither side of the central maximum when a difraction grating isilluminated with yellow-green light of wavelength =570nm.What is the maximum number of lines/m for the grating? b.) If violet light of frequency 7.9x10^14Hz is used with thissame grating, what is the highest order maximum that can beseen?

Explanation / Answer

a) the maximum number of bright fringes that can be seen oneither side of the central maximum occurs when the angle is     = 900 the bright fringes in diffraction grating is given as      dsin = m        or d =m/sin               = 4*570*10-9m / sin900               =2.280*10-6m the number of lines per centimeter is                  N = 1/d                      = 1/2.280*10-6m                      = 438596 lines/m b) frequency is f = 7.9*1014 Hz    so wavelength = c/f                             = 3*108m/s / 7.9*1014 Hz                             = 380*10-9m       we have       dsin = m          m =dsin900 / 380*10-9m               =(2.280*10-6m)*1 / 380*10-9m              = --------------------               =2.280*10-6m the number of lines per centimeter is                  N = 1/d                      = 1/2.280*10-6m                      = 438596 lines/m b) frequency is f = 7.9*1014 Hz    so wavelength = c/f                             = 3*108m/s / 7.9*1014 Hz                             = 380*10-9m       we have       dsin = m          m =dsin900 / 380*10-9m               =(2.280*10-6m)*1 / 380*10-9m              = --------------------

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.