A conducting rod slides down between two frictionless coppertracks at a constant

Question

A conducting rod slides down between two frictionless coppertracks at a constant velocity. There is a 0.75T magnetic fieldperpendicular to the rod. The rod maintains electrical contact atall times. The rod has length of 2.0m and a mass of 0.50kg. A1.0 light bulb is attached between the tops of thetracks. What is the velocity of the rod? A conducting rod slides down between two frictionless coppertracks at a constant velocity. There is a 0.75T magnetic fieldperpendicular to the rod. The rod maintains electrical contact atall times. The rod has length of 2.0m and a mass of 0.50kg. A1.0 light bulb is attached between the tops of thetracks. What is the velocity of the rod?

Explanation / Answer

           Given that the magnetic field is B = 0.75 T            Length of the rod is L = 2.0 m             massof the rod is m = 0.50 kg             theresistance R = 1.0     ---------------------------------------------------------------------         if the rod is inthe magnetic field then force on the rod is F =B*I*L       But the rod is movingdownwards with the constant velocity then the accelaration iszero                               then mg = F                                       mg = BIL                                          I = mg / BL                                             =------------ A       The induced emf is =BLv                                    v = / BL                                        =I*R / B*L                                       = ------------ m/s                                              

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