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Q1. A man throw a ball with aspeed of 14 m/s. As it passes a target point, h = 8

ID: 1743253 • Letter: Q

Question

Q1.  A man throw a ball with aspeed of 14 m/s. As it passes a target point, h = 8 mabove the level at which you release the ball, it only has ahorizontal velocity component.
(Sketch a diagram) (a). At what angle q above the horizontalmust the man throw the ball?
(b). What is the speed of the ball just as it reached thetarget? (c). What is the horizontal distance from the releasepoint to the target? (d). How long does it take to complete the projectilemotion? (e). What is the horizontal displacement of the ball atthe end? Q1.  A man throw a ball with aspeed of 14 m/s. As it passes a target point, h = 8 mabove the level at which you release the ball, it only has ahorizontal velocity component.
(Sketch a diagram) (a). At what angle q above the horizontalmust the man throw the ball?
(b). What is the speed of the ball just as it reached thetarget? (c). What is the horizontal distance from the releasepoint to the target? (d). How long does it take to complete the projectilemotion? (e). What is the horizontal displacement of the ball atthe end?

Explanation / Answer

           Given that the initial speed is U = 14 m/s            The maximum height is H = 8 m       --------------------------------------------         If the bodyprojected at an angle with the horizontal then the maximumheight is                                              H = U2 sin2 / 2g                      sin2= 2gH / U2                           = sin-1(2gH / U)                             = ---------- degrees
     The speed of the ball just reaches thetarget is = Ucos                                                                       = sin-1(2gH / U)                                                                            = --------- m/s      The horizontal distance covered is X= R/2 = U2sin2 /2g                                                                        =---------- m      Time taken to reach the maximumheight is t = Usin/g                                                                         =---------- sec