A person is riding a bicycle, and its wheels have an angularvelocity of +15.0rad

Question

A person is riding a bicycle, and its wheels have an angularvelocity of +15.0rad/s. Then, the brakes are applied and the bike is brought to auniform stop. During braking, the angular displacement of eachwheel is +15.5revolutions. (a) How much time does it take for the bike tocome to rest?
1 s

(b) What is the angular acceleration of each wheel?
2 rad/s2

Section 8.3 The Equations of RotationalKinematics
(a) How much time does it take for the bike tocome to rest?
1 s

(b) What is the angular acceleration of each wheel?
2 rad/s2
Section 8.3 The Equations of RotationalKinematics

Explanation / Answer

we have angular velocity of bicycle 0 = 15rad/s angular displacement = 15.5 rev                                     =15.5*2 rad final angular velocity = 0 rad/s a) equation of motion is 2 -02 = 2                                       02-02= 2(15.5*2rad)                                         -225m2/s2 = 2(15.5*2rad)                                               = - 225 / 2*15.5*2                                                  = -( ------- rad/s2) -ve sign indicates deceleration now using the equation = 0 +t                                    0 = 15.0 +t          simplify& calculate for t . b) from (a) we get the angular acceleration of each wheelas = -(------- rad/s2) Hope this may help you.

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