Can someone please tell me what happened here? 200(.400-R 1 ) 2 = 500(R 1 ) 2 2(

Question

Can someone please tell me what happened here? 200(.400-R1)2 = 500(R1)2 2(.400-R1) (.400-R1) = 5(R1)2 2(.16-.4R1-.4R1+R12) =5 (R1)2 2(.16+R12-.8R1)=5(R1)2 Now here is the next step and I'm not sure where the3R12 came from: 3R12+ 1.6R1-.32 = 0 Can someone please tell me what happened here? 200(.400-R1)2 = 500(R1)2 2(.400-R1) (.400-R1) = 5(R1)2 2(.16-.4R1-.4R1+R12) =5 (R1)2 2(.16+R12-.8R1)=5(R1)2 Now here is the next step and I'm not sure where the3R12 came from: 3R12+ 1.6R1-.32 = 0 Now here is the next step and I'm not sure where the3R12 came from: 3R12+ 1.6R1-.32 = 0

Explanation / Answer

from the above eq , 2(.16+R12 -.8R1) = mutiply with two then , .32+2R12 -1.6R1 = 5R12                          5R12 - 2R12 +1.6R1 - .32 = 0                        so 3R12+1.6R1 - .32 = 0                          5R12 - 2R12 +1.6R1 - .32 = 0                        so 3R12+1.6R1 - .32 = 0

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