A bullet of mass 4.00 grams speeds horizontally along thepositive x-axis with a

Question

A bullet of mass 4.00 grams speeds horizontally along thepositive x-axis with a velocity whose x component is 21.0 m/s. Itcollides with a block of mass 0.230  kilograms which isat rest on a smooth horizontal surface. The bullet completelypasses through the block and emerges on the other side. After thebullet emerges, the block has an x component of velocity 0.291 m/s.Ignore any change of mass of the block resulting from the bullet'spassage through it. What is the x component of the velocity of the center of massof the system after the collision? A bullet of mass 4.00 grams speeds horizontally along thepositive x-axis with a velocity whose x component is 21.0 m/s. Itcollides with a block of mass 0.230  kilograms which isat rest on a smooth horizontal surface. The bullet completelypasses through the block and emerges on the other side. After thebullet emerges, the block has an x component of velocity 0.291 m/s.Ignore any change of mass of the block resulting from the bullet'spassage through it. What is the x component of the velocity of the center of massof the system after the collision?

Explanation / Answer

A bullet of mass 4.00 grams speeds horizontally along thepositive x-axis with a velocity whose x component is 21.0 m/s. Itcollides with a block of mass 0.230  kilograms which isat rest on a smooth horizontal surface. The bulletcompletely passes through the block and emerges on the otherside. After the bullet emerges, the block has an xcomponent of velocity 0.291 m/s. Ignore any change of mass of theblock resulting from the bullet's passage through it. What is the x component of the velocity of the center of massof the system after the collision?

so, you just relate the before with the after.

aww i see the question now, so you want to take m_bullet*v_bullet +m_block*v_block..then all of that over m_bullet +v_bullet...so youhave (.004*4.2675)+(.230*.291)/(.004+.230) so v_cm=.359 m/s

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