please show all steps in detail The work function for silver is4.26 eV. (a) Conv

Question

please show all steps in detail
The work function for silver is4.26 eV. (a) Convert the value of the work function fromelectron volts to joules.
1 J

(b) Find the cutoff frequency for silver.
2 Hz

(c) What maximum wavelength of light incident on silver releases photoelectrons from the silver's surface?
3 m

(d) If light of energy 7.2 eV is incidenton silver, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV

(e) For photons of energy 7.2 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V please show all steps in detail
The work function for silver is4.26 eV. (a) Convert the value of the work function fromelectron volts to joules.
1 J

(b) Find the cutoff frequency for silver.
2 Hz

(c) What maximum wavelength of light incident on silver releases photoelectrons from the silver's surface?
3 m

(d) If light of energy 7.2 eV is incidenton silver, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV

(e) For photons of energy 7.2 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V

Explanation / Answer

work function W = 4.26 e V                           = 4.26 * 1.6 * 10 ^ -19 J (b). cutoff frequency f = W / h where h = planck's constant = 6.625 * 10 ^ -34 J s (c). maximum wavelength = c / f where c = speed of light = 3 * 10 ^ 8 m / s (d). maximum kinetic energy K = E - W where E = energy = 7.2 e V             W= 4.26 eV (e). stopping potential V = photon energy / charge ofelectron                                      = 7.2 eV / e                                      = 7.2 V substitue values we get answer

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