A 0.140kg baseball is traveling at 42 m/s. A batter hits theball with a net forc

Question

A 0.140kg baseball is traveling at 42 m/s. A batter hits theball with a net force of 1420 N, opposite to the direction of theball's initial motion. The bat and ball are in contact for7.5*10^-3 seconds. a) what is the mgnitude of the change in momentum of thebaseball? b) what is the final velocity of the baseball? I'm completely lost on this whole question. Any help would begreat. A 0.140kg baseball is traveling at 42 m/s. A batter hits theball with a net force of 1420 N, opposite to the direction of theball's initial motion. The bat and ball are in contact for7.5*10^-3 seconds. a) what is the mgnitude of the change in momentum of thebaseball? b) what is the final velocity of the baseball? I'm completely lost on this whole question. Any help would begreat.

Explanation / Answer

given the mass of the ball is m = 0.140kg the initial velocity of the ball is v = 42 m/s the force F = 1420 N the time of contact t = 7.5 *10-3 s a ) the change in the momentum = force *time                                                    =F* t b ) let the final velocity of the ball is V then        change in the momentum= mv - mV                         F*t = mv - mV                          V = v - F *t / m   plug in the values and calculate

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