In moving a standard computer mouse, a userapplies a horizontal force of 6.00×10

Question

In moving a standard computer mouse, a userapplies a horizontal force of 6.00×102 N. The mouse has a mass of 125 g.(a) What is the acceleration of the mouse? Ignore forces likefriction that oppose its motion. (b) Assuming it starts from rest,what is its speed after moving 0.159 m across a mousepad? In moving a standard computer mouse, a userapplies a horizontal force of 6.00×102 N. The mouse has a mass of 125 g.(a) What is the acceleration of the mouse? Ignore forces likefriction that oppose its motion. (b) Assuming it starts from rest,what is its speed after moving 0.159 m across a mousepad?

Explanation / Answer

Acceleration = force / mass = 6.00×102 N / 0.125 kg = 0.48m/s2 If the mouse moved from rest its initial velocity is zero. sothat               v = (2 a s)                  = 2*0.48 m/s2*0.159m = 0.39 m/s If the mouse moved from rest its initial velocity is zero. sothat               v = (2 a s)                  = 2*0.48 m/s2*0.159m = 0.39 m/s

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