QuestionDetails: A billiard ball is moving in positive x direction at 3 m/s ands

Question

QuestionDetails: A billiard ball is moving in positive x direction at 3 m/s andstrikes another billiard ball movin in positive y direction. Afterthe collision, the second ball stops. Two balls have identicalmass. What is the speed of the first ball after collision? and What is the direction of the first ball relative to positive xaxis after the collision? QuestionDetails: A billiard ball is moving in positive x direction at 3 m/s andstrikes another billiard ball movin in positive y direction. Afterthe collision, the second ball stops. Two balls have identicalmass. What is the speed of the first ball after collision? and What is the direction of the first ball relative to positive xaxis after the collision? QuestionDetails: A billiard ball is moving in positive x direction at 3 m/s andstrikes another billiard ball movin in positive y direction. Afterthe collision, the second ball stops. Two balls have identicalmass. What is the speed of the first ball after collision? and What is the direction of the first ball relative to positive xaxis after the collision?

Explanation / Answer

Applying conservation of momentum we get               v1f = (m1v1i +m2v2i) / m1 To find this value you have to mention the speed ofbrilliard ball in the y-direction. Along the x-direction                m1v1i    = m1v1f cos
Therefore = cos-1(v1i  / v1f )

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