(a) A charge of -340 e is uniformly distributed along acircular arc of radius 4.

Question

(a) A charge of -340e is uniformly distributed along acircular arc of radius 4.05 cm,which subtends an angle of 37°. What is the linearcharge density along the arc?
I got this part because its Q/Lwhich is
-340*(1.620*10^-19) / [2*pi*.0405 * (37/360)]

(b) A chargeof -340e is uniformlydistributed over one face of a circular disk ofradius 2.10 cm. What is thesurface charge density over that face?
Shouldn't B just be -340*(1.620*10^-19) /[pi*(.0405)^2]
(c) A chargeof -340e is uniformlydistributed over the surface of a sphere ofradius 2.10 cm. What is thesurface charge density over that surface?
Shouldn't C just be -340*(1.620*10^-19) / [(4/3)pi*(.0405)^3]
(d) A chargeof -340e is uniformlyspread through the volume of a sphere of radius 2.10 cm. What is the volume charge density inthat sphere?
When I entered the values for Band C they were wrong. I need some guidence.
I got this part because its Q/Lwhich is
-340*(1.620*10^-19) / [2*pi*.0405 * (37/360)]

(b) A chargeof -340e is uniformlydistributed over one face of a circular disk ofradius 2.10 cm. What is thesurface charge density over that face?
Shouldn't B just be -340*(1.620*10^-19) /[pi*(.0405)^2]
(c) A chargeof -340e is uniformlydistributed over the surface of a sphere ofradius 2.10 cm. What is thesurface charge density over that surface?
Shouldn't C just be -340*(1.620*10^-19) / [(4/3)pi*(.0405)^3]
(d) A chargeof -340e is uniformlyspread through the volume of a sphere of radius 2.10 cm. What is the volume charge density inthat sphere?
When I entered the values for Band C they were wrong. I need some guidence.
(b) A chargeof -340e is uniformlydistributed over one face of a circular disk ofradius 2.10 cm. What is thesurface charge density over that face?
Shouldn't B just be -340*(1.620*10^-19) /[pi*(.0405)^2]
(c) A chargeof -340e is uniformlydistributed over the surface of a sphere ofradius 2.10 cm. What is thesurface charge density over that surface?
Shouldn't C just be -340*(1.620*10^-19) / [(4/3)pi*(.0405)^3] Shouldn't C just be -340*(1.620*10^-19) / [(4/3)pi*(.0405)^3]
(d) A chargeof -340e is uniformlyspread through the volume of a sphere of radius 2.10 cm. What is the volume charge density inthat sphere?
When I entered the values for Band C they were wrong. I need some guidence.

Explanation / Answer

Given :     B ) r = 2.10 cm = 0.0210           = q / A     [ A = r2 ]                 = -340*(1.620*10-19) /[*(.0210)2]                         = ------ C / m2     C )   r = 2.10 cm =0.0210       Surface chrage density           s= q / 4A     [ A = r2 ]               =q / 4 r2                         = -340*(1.620*10-19) /[(4/3)*(.0210)2]              = -----    C / m2     Solve the above, you will get the correctvalues      I hiope it helps you     Solve the above, you will get the correctvalues      I hiope it helps you

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.