-Given the data of a ball being vertically launched at a 90degree angle. Mass of
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-Given the data of a ball being vertically launched at a 90degree angle. Mass of ball = 9.3 grams Diameter of ball = .025m Avg Launch Speed = 3.26m/s Initial Launch Height of the ball = .28m Maximum Height reached by ball = .741m -Find the following from the given data: Initial kinetic energy of the ball = ? Initial potential energy = ? Final potential energy = ? Actual change in potential energy = ? Change in potential energy of ball (assuming conservation ofmechanical energy) = ? Maximum height ball could reach (assuming conservation ofmechanical energy) = ? Work done by the nonconservative force of air resistance onthe ball = ? --Several parts but i believe each are short steps, feel freeto answer in multiple posts if needed & Please show work. -Given the data of a ball being vertically launched at a 90degree angle. Mass of ball = 9.3 grams Diameter of ball = .025m Avg Launch Speed = 3.26m/s Initial Launch Height of the ball = .28m Maximum Height reached by ball = .741m -Find the following from the given data: Initial kinetic energy of the ball = ? Initial potential energy = ? Final potential energy = ? Actual change in potential energy = ? Change in potential energy of ball (assuming conservation ofmechanical energy) = ? Maximum height ball could reach (assuming conservation ofmechanical energy) = ? Work done by the nonconservative force of air resistance onthe ball = ? --Several parts but i believe each are short steps, feel freeto answer in multiple posts if needed & Please show work.Explanation / Answer
a. k.e. K = (1/2)* m * v2 = 0.5 * 9.3 *10-3 *3.262 = 4.94 *10-2 J b. Initialp.e. Ui = m* g * hi = 9.3 *10-3 * 9.8 *0.28 = 2.55 *10-2 J c. Finalp.e. Uf = m* g * hf = 9.3 *10-3 * 9.8 *0.741 = 6.75 *10-2 J d. Chance inp.e. U = Uf - Ui = 6.75* 10-2 - 2.55 *10-2 = 4.20 *10-2 J e. Initialenergy Ei = Ui + K = 2.55* 10-2 + 4.94 *10-2 = 7.49 *10-2 J netchenge inenergy = Ei - Uf = 7.49* 10-2 - 6.75 *10-2 = 7.4 *10-3 J f. Maximum height that ballcould reach is given by m * g *hmax = Ei 9.3 *10-3 * 9.8 *hmax = 7.49 *10-2 hmax = 0.822m ( this height is abovehi, if you need total height add 0.280 m) g. Work done byfriction W = initialenergy - finalenergy = 7.49 *10-2 - 6.75 *10-2 W = 7.40* 10-3 J W = 7.40* 10-3 JRelated Questions
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