The drawing depicts a copper loop lying flat on a table (not shown)and connected
ID: 1746383 • Letter: T
Question
The drawing depicts a copper loop lying flat on a table (not shown)and connected to a battery via a closed switch. The currentI in the loop generates the magnetic field lines shown inthe drawing. The switch is then opened and the current goes tozero. There are also two smaller conducting loops A and B lyingflat on the table, but not connected to batteries. Determine thedirection of the induced current in (a) loop A and (b) loop B.Specify the direction of each induced current to be clockwise orcounterclockwise when viewed from above the table.The drawing is in the book, I dont know how to put it on here. Imsorry.
Any help or tips will be greatly appreciated though. THANK YOU!
Explanation / Answer
Given : a.) Loop A-When viewed from the table, the current in loop Awill flow in clockwise direction. The magnetic field is directedvertically downward, and as the current in the loop falls, magneticflux in loop A in downward direction decreases. According toLenz's law, current flows in the direction the the loop A that fluxin downward direction increases. (This is also proved by theRHR) b.) Loop B- The direction of the induced current flowsin the counterclockwise direction. Magnetic flux in loop B isin vertically upward direction so when the current in the main loopdecreased, the flux in loop B decreases in upward direction. Lenz'slaw states that current flows in loop B in a direction to producemagnetic flux in upward direction a.) Loop A-When viewed from the table, the current in loop Awill flow in clockwise direction. The magnetic field is directedvertically downward, and as the current in the loop falls, magneticflux in loop A in downward direction decreases. According toLenz's law, current flows in the direction the the loop A that fluxin downward direction increases. (This is also proved by theRHR) b.) Loop B- The direction of the induced current flowsin the counterclockwise direction. Magnetic flux in loop B isin vertically upward direction so when the current in the main loopdecreased, the flux in loop B decreases in upward direction. Lenz'slaw states that current flows in loop B in a direction to producemagnetic flux in upward direction I hope it helps youRelated Questions
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