from a hot reservoir at a temp of T1, carnot engine A takes aninput heat fo 5550
ID: 1747263 • Letter: F
Question
from a hot reservoir at a temp of T1, carnot engine A takes aninput heat fo 5550 J, delivers 1750J of work and rejects heat to acold reservoir that has a temp of 503K. this cold reservior @503Kalso serves as the hot reservoir for engine B, which uses therejected heat of the first engine as input heat. engine Balso delivers 1750 J of work, while rejecting heat to an evencolder reservoir that has a temp of T2. Find the temps of T1and T2 i'm thinkin backwards from a hot reservoir at a temp of T1, carnot engine A takes aninput heat fo 5550 J, delivers 1750J of work and rejects heat to acold reservoir that has a temp of 503K. this cold reservior @503Kalso serves as the hot reservoir for engine B, which uses therejected heat of the first engine as input heat. engine Balso delivers 1750 J of work, while rejecting heat to an evencolder reservoir that has a temp of T2. Find the temps of T1and T2 i'm thinkin backwardsExplanation / Answer
For engine A : ------------- input heat Q = 5550 J rejected heat Q ' = Q - Work = 5550 - 1750 = 3800 J For carnot engine T / T ' = Q / Q ' from this hot reservoir temperature T = Q T ' / Q' = ( 5550 * 503 ) / 3800 = 734.64 K For engine B : ------------- input heat Q = 3800 J rejected heat Q ' = Q - Work = 3800 - 1750 = 2050 J For carnot engine T / T ' = Q / Q ' from this hot reservoir temperature T ' = Q 'T / Q = ( 2050 * 503 ) / 3800 = 271.35 K For engine B : ------------- input heat Q = 3800 J rejected heat Q ' = Q - Work = 3800 - 1750 = 2050 J For carnot engine T / T ' = Q / Q ' from this hot reservoir temperature T ' = Q 'T / Q = ( 2050 * 503 ) / 3800 = 271.35 KRelated Questions
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