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A camper is about to drink his morning coffee. He pours 400grams of coffee, init

ID: 1747295 • Letter: A

Question

A camper is about to drink his morning coffee. He pours 400grams of coffee, initially at 75.0 degrees Celsius, into a 250 galuminum cup, initially at 16 degrees Celsius. What is theequilibrium temp. of the coffee-cup system, assuming no heat islost to the surroundings? The specific heat of aluminum is900 J/(kg K). Assume that the specific heat of coffee is the sameas the specific heat of water.
A) 65 degrees celsius B) 45.5 degrees celsius C) 68 degrees celsius D) 71 degrees celsius E) 62 degrees celsius
How do you solve this? Which equations do you use?
A) 65 degrees celsius B) 45.5 degrees celsius C) 68 degrees celsius D) 71 degrees celsius E) 62 degrees celsius
How do you solve this? Which equations do you use?

Explanation / Answer

mass of coffee m = 400 g = 0.4 kg initial temp of coffee   t = 75 oC mass of aluminium M = 250 g = 0.25 kg initial temp t ' = 16 oC The specific heat of aluminum C = 900 J/(kgK) specific heat of coffee c = specific heat ofwater.                                    = 4186 J / kg o C heat lost by coffee = heat gain by aluminium             m c dt = MC dt ' 0.4 *4186* (75-T ) = 0.25 * 900 ( (T - 16 )                   75-T = 0.1343 ( T -16 )                           = 0.1343 T - 2.15 from this final equilibrium temperature T= 68 oC