A 1.2 kg block is held a height of 10 m above the floor. a)calculate work while
ID: 1747479 • Letter: A
Question
A 1.2 kg block is held a height of 10 m above the floor. a)calculate work while holding the object at this height. b) if the block is dropped from this height, calculate thekinetic energy and gravitational potential energy of the objectwhen it reaches a height of 4 m from the floor. A 1.2 kg block is held a height of 10 m above the floor. a)calculate work while holding the object at this height. b) if the block is dropped from this height, calculate thekinetic energy and gravitational potential energy of the objectwhen it reaches a height of 4 m from the floor.Explanation / Answer
A 1.2 kg block is held a height of 10 mabove the floor. a) calculate work while holding theobject at this height. Not clear. Wok done by a biological system is beyond this forum so weshould not concern ourself with that. If we support the block byanything the work done by that 'anything' on the block will bezero. Raising the block however will require work W. Where W= mgH; H=10m b) if the block is dropped from thisheight, calculate the kinetic energy and gravitationalpotential energy of the object when it reaches aheight of 4 m from the floor. Pemax = Ke(h) + Pe(h) where h -is height Pemax = mgH; H= 10 m h =4m The gravitational potential energy at h=4m is Pe(h) = mgh; h =4m Pe(4) = 1.2 x 9.81x4 Pe = 47.1J Ke= 0.5mV2 ; V=gt and t =[(2(H-h)/g] tNow Ke= 0.5m (g [(2(H-h)/g] )2 Ke= 0.5m [(2(H-h)g] Ke= mg [((H-h) Ke= 1.2 x 9.81( 10-4) Ke= 70.6 J To check Pemax = mgH = 1.2 x 9.81 x10 Pemax = 117.7 J Pemax = 47.1 + 70.6=117.7 J (confirmed) Ke= 0.5m [(2(H-h)g] Ke= mg [((H-h) Ke= 1.2 x 9.81( 10-4) Ke= 70.6 J To check Pemax = mgH = 1.2 x 9.81 x10 Pemax = 117.7 J Pemax = 47.1 + 70.6=117.7 J (confirmed) Ke= 0.5m [(2(H-h)g] Ke= mg [((H-h) Ke= 1.2 x 9.81( 10-4) Ke= 70.6 J To check Pemax = mgH = 1.2 x 9.81 x10 Pemax = 117.7 J Pemax = 47.1 + 70.6=117.7 J (confirmed) Ke= mg [((H-h) Ke= 1.2 x 9.81( 10-4) Ke= 70.6 J To check Pemax = mgH = 1.2 x 9.81 x10 Pemax = 117.7 J Pemax = 47.1 + 70.6=117.7 J (confirmed)
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