Light of wavelength 587.6 nm illuminates aslit, of width 0.74 mm. (a) At what di

Question

Light of wavelength 587.6 nm illuminates aslit, of width 0.74 mm. (a) At what distance from the slit should ascreen be placed if the first minimum in the diffraction pattern isto be 0.84 mm from the centralmaximum?
1
Your answer differs from the correct answerby orders of magnitude. m
(b) Calculate the width of the central maximum.
2
Your answer differs from the correct answerby 10% to 100%. mm (a) At what distance from the slit should ascreen be placed if the first minimum in the diffraction pattern isto be 0.84 mm from the centralmaximum?
1
Your answer differs from the correct answerby orders of magnitude. m
(b) Calculate the width of the central maximum.
2
Your answer differs from the correct answerby 10% to 100%. mm

Explanation / Answer

Light of wavelength = 587.6 nm
                                 = 587. 6 * 10 ^ -9 m
slit width d = 0.74 mm.
                  =0.74 * 10 ^ -3 m
distance of the first minimum from the central maximumon screen y = 0.84 mm = 0.84 * 10 ^ -3 m we know condition for 1 st minima is d sin = at small angle is sin ~ tan = y /D where D = distance of the screen from slit substitue we get d ( y /D ) = from this D = d y /                   = 1.057 m (b). width of central maximum Y = 2 y                                                  =1.68 * 10 ^ -3 m                                                 = 1.68 mm we know condition for 1 st minima is d sin = at small angle is sin ~ tan = y /D where D = distance of the screen from slit substitue we get d ( y /D ) = from this D = d y /                   = 1.057 m (b). width of central maximum Y = 2 y                                                  =1.68 * 10 ^ -3 m                                                 = 1.68 mm

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