a uniform rod lenth 15 meters is mounted to rotate freelyabout a horizontal axis

Question

a uniform rod lenth 15 meters is mounted to rotate freelyabout a horizontal axis that is perpendicular to the rod and thatpasses through the rod at a point 5 meters from one end of the rod.if the rod is released from rest in a horizontal position, what isthe angular speed of the rod as it rotates through its lowestpoint? please help asap!! will rate a uniform rod lenth 15 meters is mounted to rotate freelyabout a horizontal axis that is perpendicular to the rod and thatpasses through the rod at a point 5 meters from one end of the rod.if the rod is released from rest in a horizontal position, what isthe angular speed of the rod as it rotates through its lowestpoint? please help asap!! will rate

Explanation / Answer

According to conservation of mechanical energy Ki + Ui = Kf + Uf Ki = 0 Ui = m * g * (L/2 - r) Kf = (1/2)Iw^2 Uf = 0 or 0 + m * g * (L/2 - r) = (1/2)Iw^2 + 0 or m * g * (L/2 - r) = (1/2) * (m * L^2/12) * w^2 w^2 = (24/L^2) * g * (L/2 - r) or w = (1/L) * (24 * g * (L/2 - r)) L = 15 m,g = 9.8 m/s^2 and r = 5 m

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