Gas in a container is at a pressure of 1.4atm and a volume of 7.0 m 3 . (a) What

Question

Gas in a container is at a pressure of 1.4atm and a volume of 7.0 m3. (a) What is the work done on the gasif it expands at constant pressure to twice its initial volume?
Enter anumber. 1 J

(b) What is the work done on the gas if it is compressedat constant pressure to one-quarter its initial volume?
Enter anumber. 2 J (a) What is the work done on the gasif it expands at constant pressure to twice its initial volume?
Enter anumber. 1 J

(b) What is the work done on the gas if it is compressedat constant pressure to one-quarter its initial volume?
Enter anumber. 2 J Enter anumber. Enter anumber.

Explanation / Answer

a) Formula for calculating the value of the workdone onthe gas if it expands at constant pressure is                 W = PdV                      = (1.4atm)(7.0 m3)                       =(1.4)(1.013*105Pa)(7.0m3)                      = 9.93*105J b) Here in this case V1 = V and V2 = (1/4)V Then work done on the gas if it is compressed atconstant pressure is            W= P(V2 - V1)                = (1.4)(1.013*105Pa)[(1/4)V - V]                = (1.4)(1.013*105Pa)[-(3/4)V]               = -(3/4)(1.4)(1.013*105Pa)(7.0m3)

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.