Under constant pressure, the temperature of 2.40 mol of an ideal monatomic gas i
ID: 1748856 • Letter: U
Question
Under constant pressure, the temperature of 2.40 mol of an ideal monatomic gas is raised12.0 K. (a) What is the work W done by thegas?1 J
(b) What is the energy transferred as heat Q?
2 J
(c) What is the change Eint in theinternal energy of the gas?
3 J
(d) What is the change K in the average kineticenergy per atom?
4 J (a) What is the work W done by thegas?
1 J
(b) What is the energy transferred as heat Q?
2 J
(c) What is the change Eint in theinternal energy of the gas?
3 J
(d) What is the change K in the average kineticenergy per atom?
4 J
Explanation / Answer
Given : n = 2.40 mol T = 12.0 K (a) Workdone : W = n R T = 2.40 * 8.314 * 12 = 239.44 J (b) Q = n cpT = 2.40 * (5/2) R * 12 = 2.40 * ( 5 /2) * 8.314 * 12 = 598.608 J (c) Eint = Q - W = 598.608 - 239.44 = 359.168 J (d) K = 3/2 K T = 3 /2 * 1.38 x 10-23* 12 = 2.484 x 10-22 J Hope this helps u!Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.