1) A 1mg dust particle carrying a net charge of 1nC, is dropped btwn the plates

Question

1)   A 1mg dust particle carrying a net charge of 1nC, is dropped btwn the plates of a parallel-plate capacitor. Theplates are vertical, separated by 5mm and have sides that are 1 cmsquare. The electron is released at the top edge of the unchargedcapacitor and falls completely through the capacitor at which pointis strikes the ground. This position is marked. The capacitor isthen charged to 10 V and the electron is again released from thetop of the plates. Determine the horizontal distance from where theelectron now strikes the ground. Express answer in mm..The answeris 2 …but how do you get it. 2)   A 10 m copper rod has a diameter of 1cm and theresistance of 4.5 ohms at 20 degrees C. Find the rod’sresistance when it is heated to 300 degree C. Specify your answerin ohms…the answer is 9.45 but how do you get it? 1)   A 1mg dust particle carrying a net charge of 1nC, is dropped btwn the plates of a parallel-plate capacitor. Theplates are vertical, separated by 5mm and have sides that are 1 cmsquare. The electron is released at the top edge of the unchargedcapacitor and falls completely through the capacitor at which pointis strikes the ground. This position is marked. The capacitor isthen charged to 10 V and the electron is again released from thetop of the plates. Determine the horizontal distance from where theelectron now strikes the ground. Express answer in mm..The answeris 2 …but how do you get it. 2)   A 10 m copper rod has a diameter of 1cm and theresistance of 4.5 ohms at 20 degrees C. Find the rod’sresistance when it is heated to 300 degree C. Specify your answerin ohms…the answer is 9.45 but how do you get it?

Explanation / Answer

Temperature coefficient of resistivity () of copper =3.9*10-3 / oC Now formula for the resistance of copper at the temperature300oC is                 R = Ro[1 + T]                    = (4.5)[1 + (3.9*10-3 /oC)(300oC - 20oC)]                    = 9.414

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