If the clock losses 10 min/day when the length of the pend is30 inches. With wha

Question

If the clock losses 10 min/day when the length of the pend is30 inches. With what length pendulum will the pend keepperfect time? Equations that may help:    g1/g2=R22/ R12    Period 2/period 1 = R2/R1(l2/ l1)1/2 R is radius and l is length g is usually 32 If the clock losses 10 min/day when the length of the pend is30 inches. With what length pendulum will the pend keepperfect time? Equations that may help:    g1/g2=R22/ R12    Period 2/period 1 = R2/R1(l2/ l1)1/2 R is radius and l is length g is usually 32 R is radius and l is length g is usually 32

Explanation / Answer

we know   1 day = 24 h = 24 * 60 min                                       =1440 min the pendulum loses 10 minutes per day So, time T ' = 1430 min for exact clock time T = 1440 min we know the period of a pendulum T = 2[L/g]      Or ( T ' / T ) = [ L ' / L ] from this 1430 / 1440 = [ 30 in / L]                            L = 30.421 inches we know the period of a pendulum T = 2[L/g]      Or ( T ' / T ) = [ L ' / L ] from this 1430 / 1440 = [ 30 in / L]                            L = 30.421 inches

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